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The question is ambiguous because there is no sign shown before the final 6.
Assume it is +6 since -6 would make factorisation very difficult.
Thus the equation is 6b2 - 13b + 6 = 0
Then 6b2 - 4b - 9b + 6 = 0
or 2b(3b - 2) - 3(3b - 2) = 0
ie (3b - 2)(2b - 3) = 0
then 3b -2 = 0 or 2b - 3 = 0
so 3b =2 or 2b = 3
ie b = 2/3 or b = 3/2
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Solve the quadratic equation using factoring 9x2 - 16 equals 0?
(3x+4)(3x-4)=0 x=±4/3
Solve by factoring 9xsquared plus 6x minus 8 equals 0?
9x2+6x-8 = 0 (3x+4)(3x-2) = 0 Therefore: x = -4/3 or x = 2/3
What equation could be used to solve y² plus 7y equals 18 by factoring?
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Solve the quadratic equation using factoring 9x2 - 16 equals 0?
(3x+4)(3x-4)=0 x=±4/3
How do you solve q squared plus 16q equals 0?
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Solve by factoring 9xsquared plus 6x minus 8 equals 0?
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What equation could be used to solve y² plus 7y equals 18 by factoring?
y2+7y=18 y2+7y-18=0 (y+9)(y-2)=0 y=-9 & y=2
How do you solve 2Sinx 1 equals 0?
2sinx+1 equals 0
How do you solve n2 equals 20 plus n by factoring?
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Solve by factoring 3x2 equals -9?
3x2 = -9 (divide both sides by 3) x2 = -3 (x would have to be the square root of -3) x = ±√-3 x = ±√3i Since you want to solve by factoring: x2 = -3 add 3 to both sides x2 + 3 = 0 x2 - 3i2 = 0 x2 - (√3i)2 = 0 Factor: (x - √3i)(x + √3i) = 0 x - √3i = 0 or x + √3i = 0 x = √3i or x = -√3i
How do you solve the math problem a squared plus 2a minus 3 equals 0?
a2 + 2a - 3 = 0(a + 3)(a - 1)a = - 3a = 1Simple factoring where you ask yourself; what two factors of - 3 add up to 2?
How do you solve y-2y'-3y equals 0?
For y - 2y - 3y equals 0, y equals 0.
X2-14x equals -49 solve by factoring?
Re-arranging, x2 - 14x +49 = 0 Factorising, (x-2)(x-2) = 0, hence x=2.
What is 2x2 - 12x - 54 equals o find x?
2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
