The expression you presented is not an equation. Do you mean ax2 + bx = c? Do you mean to solve it for x? I'm assuming that's the case, but you need to be more clear on your question. To solve for x then, the technique to use is called completing the square: ax2 + bx = c Multiply both sides by a: a2x2 + abx = ac Add the square of b/2 to both sides: a2x2 + abx + (b/2)2 = ac + (b/2)2 We now have a perfect square on the left, simplify: (ax + b/2)2 = ac + b2 / 4 (ax + b/2)2 = (4ac + b2) / 4 And now solve for x: ax + b/2 = ±[(4ac + b2) / 4]1/2 ax + b/2 = ± √(4ac + b2) / 2 ax = [-b ± √(4ac + b2)] / 2 x = [-b ± √(4ac + b2)] / 2a
(b - x)(ab - xy)
x/a + x/b = 1Taking x as a common factor: x*(1/a + 1/b) = 1Adding the fractional parts x*(b/ab + a/ab) = 1or x*[(b + a)/ab] = 1Multiply both sides by (a+b)/abx = (a+b)/abAnother Approuch:-x/a+x/b = 1Multiply all terms by ab to eliminate the fractions:bx+ax = abFactorise:x(a+b) = abDivide both sides by (a+b):x = ab/(a+b)
Consider the square ABCD whose diagonals, AC and BD, meet at X.AB is parallel to DC and AC intercepts them. Therefore <BAX = <DCX. AB is parallel to DC and BD intercepts them. Therefore <ABX = <CDX. AB = CD. Therefore triangle ABX is congruent to triangle CDX (SAS). So AX = XC ie X is the midpoint of AC and BX = XB ie X is the midpoint of BD. ie the diagonals bisect each other.
That means that the growth is equal to, or similar to, an exponential function, which can be written (for example) as abx, for constants "a" and "b". One characteristic of exponential growth is that the function increases by the same percentage in the same time period. For example, it increases 5%, or equivalently by a factor of 1.05, every year.
Basically, in an exponential expression (or equation) you have the independent variable in the exponent. For example: 5 times 10x The general form of an exponential function can be written as: abx or: aekx where a, b, and k are constants, and e is approximately 2.718. Note that just having a power doesn't mean you have an exponential equation. For example, in x3 the variable does NOT appear in the exponent, so it is not an exponential expression.
ABX Air was created in 1980.
The expression you presented is not an equation. Do you mean ax2 + bx = c? Do you mean to solve it for x? I'm assuming that's the case, but you need to be more clear on your question. To solve for x then, the technique to use is called completing the square: ax2 + bx = c Multiply both sides by a: a2x2 + abx = ac Add the square of b/2 to both sides: a2x2 + abx + (b/2)2 = ac + (b/2)2 We now have a perfect square on the left, simplify: (ax + b/2)2 = ac + b2 / 4 (ax + b/2)2 = (4ac + b2) / 4 And now solve for x: ax + b/2 = ±[(4ac + b2) / 4]1/2 ax + b/2 = ± √(4ac + b2) / 2 ax = [-b ± √(4ac + b2)] / 2 x = [-b ± √(4ac + b2)] / 2a
As of July 2014, the market cap for Barrick Gold Corporation (ABX) is $21,313,453,826.40.
Antibiotics
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antibiotics?
Antibiotics
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x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
Y=abx + c is the general form.