5 = -2x + 110x - 1,000
5 = 108x - 1,000
1,005 = 108x
335/36 = x
(2x)ysquared
(2-r)e-rr
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
(4 ± i2) where i2 = -1
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
(2x)ysquared
(2-r)e-rr
x=4 x=0
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
(4 ± i2) where i2 = -1
x2 + x2 = 2x2
You cannot solve, without equating it to something. As given it is just an expression. However it can be factored. x^(2) + 7x +12 ( x + 3)(x + 4) Factored but NOT solved. However, it we equate to 'zero(0)' then it can be solved. ( x + 3)( x + 4) = 0 X + 3 = 0 x = -3 Similarly x + 4 = 0 x = -4 Are the solutions (solved).
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2 = 6482 = 64x = 8
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4