False
v=1/2 a t2
t=5s
a=9.81m/s2
v=122.625 m/s
49
49
176.4 meters
,033
9.8m/s(5)= 49
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
49
29.4
49
176.4 meters
The speed of the rock after 5 seconds of free fall would not be 100. The speed of an object in free fall increases by 9.8 m/s every second. After 5 seconds, the speed of the rock would be 49 m/s (approximately), assuming no air resistance.
,033
9.8m/s(5)= 49
The speed of an object dropped off a cliff after 5 seconds, neglecting air resistance, is given by the equation: v = gt, where v is the final speed, g is the acceleration due to gravity (9.8 m/s^2), and t is the time it has been falling. Plugging in the values gives v = 9.8 m/s^2 * 5 s = 49 m/s. So, the speed of the object after 5 seconds will be 49 m/s.
The acceleration of gravity is 9.8 m/s2Speed after 3 sec = (9.8 x 3) = 29.4 m/s
river
An object dropped from a height without any initial velocity, a skydiver falling towards the ground before deploying their parachute, and a rock falling off a cliff are all examples of free fall.