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The area of a rectangle is 60 in to the second power the length is 4 inches greater then the width find the length?
Suppose length is x inches
Then length is x-4 inxhes
So area is x*(x-4) = x2 - 4x sq inches
Now,
x2 - 4x = 60
so x2 - 4x - 60 = 0
x2 - 10x + 6x - 60 = 0
x(x - 10) + 6(x - 10) = 0 ie (x - 10)*(x + 6) = 0
So x - 10 = 0 or x + 6 = 0
So x= 10 or x = -6
Since x is a length it must be > 0 so x = 10 inches.
What else can I help you with?
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