Left
(y - 3) = a(x - 1)2 y = a(x - 1)2 + 3 4 = a(4 - 1)2 + 3 1 = 9a a = 1/9 y = 1/9 (x - 1)2 + 3
No, I can't.
The graph of the solution set of a quadratic inequality typically represents a region in the coordinate plane, where the boundary is formed by the parabola defined by the corresponding quadratic equation. Depending on the inequality (e.g., (y < ax^2 + bx + c) or (y > ax^2 + bx + c)), the solution set will include points either above or below the parabola. The parabola itself may be included in the solution set if the inequality is non-strict (e.g., ( \leq ) or ( \geq )). The regions of the graph where the inequality holds true are shaded or highlighted to indicate the solution set.
Please include the equation.
Down
right apex. hope that helps
If the equation of the parabola isy = ax^2 + bx + c, then it opens above when a>0 and opens below when a<0. [If a = 0 then the equation describes a straight line, and not a parabola!].
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Go study
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
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The coordinates will be at the point of the turn the parabola which is its vertex.
The y coordinate is given below:
A parabola that opens upward is a U-shaped curve where the vertex is the lowest point on the graph. It can be represented by the general equation y = ax^2 + bx + c, where a is a positive number. The axis of symmetry is a vertical line passing through the vertex, and the parabola is symmetric with respect to this line. The focus of the parabola lies on the axis of symmetry and is equidistant from the vertex and the directrix, which is a horizontal line parallel to the x-axis.
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