810: quotient 1, remainder 1
1005
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
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It is 1.1 = 0*12152128 r 1
25
301
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.
810: quotient 1, remainder 1
1005
449 is the smallest number that satisfies those requirements.
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
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