0
The position function x of f of a particle moving along an x axis is x equals 4.0-6.0 t2 with x in meters and t in seconds At what time and where does the particle momentarily stop?
Toyvo2
x = 4 - 6 t2
Speed = (dx/dt) = - 12 t
Speed = 0 when t = 0
x(0) = 4
The particle stops at [ t = 0 ], located at [ x = 4 ].
The physical reality is: The particle started at [ x = 4 ], and once it started moving, it never stopped.
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
The displcement x is m from the equilibrium position of a particle moving with SHM is given by x equals 0.05sint where t is the time in seconds measured from an instant when x equals o state the ampli?
The amplitude of the Simple Harmonic Motion is 0.05.
How is distance travel by particle projected vertically upward with initial velocity 25 meter per seconds is 2.5 mt in 3rd second of motion?
i
What is the net displacement of the particle between 0 seconds and 80 seconds?
That would besqrt[ (x80 - x0)2 + (y80 - y0)2 ) at an angle of tan-1 (y80 - y0) / (x80 - x0)or(x80 - x0) i + (y80 - y0) j
What if your friend is bragging about his motorcycle He claims that it can go from a stopped position to 50 miles per hour in three seconds He is describing the motorcycle's?
acceleration.
How many times does a 5 appear on a 12 hour clock in 24 hours?
On an analog clock, there is one 5 that is always apparent.On a digital clock, it depends whether or not seconds are displayed. If not, the hours position shows 5 twice per day, the tens of minutes position shows 5 once per hour or 24 times per day, and the minutes position shows 5 six times per hour, which is 144 times per day.2 times/day + 24 times/day + 144 times/day = 170 times/dayIf seconds are displayed, in addition to the 170 times/day you have in the tens of seconds position a 5 once per minute, which is 1440 (60 * 24) times per day, and in the seconds position you have a 5 six times per minute, which is 8640 (1440 * 6) times per day.170 times/day + 1440 times/day + 8640 times/day = 10,250 times/day
A particle of mass 3kg moves under a force of 4i plus 8j plus 10k . if the particles start from rest and was at the origin initially its new coordinATE AFTER 3 SEC will be?
To find the new coordinates of the particle after 3 seconds, we need to integrate the acceleration function twice. Given the force function F = 4i + 8j + 10k, we can find the acceleration using Newton's second law (F = ma) and then integrate it twice to find the position function. The final position coordinates can be determined by plugging in t=3 seconds into the position function.
What is the velocity of the moving object at time 5 second?
To determine the velocity of a moving object at a specific time, you would need the object's position function or acceleration function. If you have the position function, you can differentiate it to get the velocity function and then substitute t=5 seconds. If you have the acceleration function, integrate it with respect to time to get the velocity function and then substitute t=5 seconds.
Why does my computer pause momentarily every six minutes and 12 seconds?
You're an idiot.
What is the average acceleration of the particle between 0 seconds and 4 seconds?
it's answer "c"
What is the position of the ball at 7.5 seconds?
What is the position of the ball at 7.5 seconds
A subatomic particle known as a pion has a lifespan of 000000026 seconds How long does the particle exist from the perspective of an observer if the particle moves past the observer at 67c?
From the observer's perspective, due to time dilation effects at high speeds, the pion would exist for approximately 0.000000041 seconds.
What is the distance traversed by the particle between 0 seconds and 6 seconds?
The distance, expressed in inches, is(1.2) x (the particle's average speed, in feet per minute) .
What is the average velocity of the particle from rest to 9 seconds?
The answer will depend on its acceleration.
What is the displacement of the object from 2 seconds to 6 seconds?
To find the displacement from 2 seconds to 6 seconds, you need to calculate the change in position of the object during that time interval. This can be done by subtracting the position of the object at 2 seconds from its position at 6 seconds. The result will give you the displacement of the object during that time period.
What is the period of a particle that has a frequency of 315 hertz?
The period of a particle is the inverse of its frequency. Therefore, for a particle with a frequency of 315 Hz, the period can be calculated as 1/315 Hz, which equals 0.00317 seconds.
The energy of a certain particle is 3.86 joueles if this particle loses 0.105 joule of energy every 30 seconds what will its energy be after 8 minutes?
2.18J
What is the position of the ball at 10 seconds?
10m
