If you reach into the bag, grasp, and withdraw your hand,
the probability of pulling something out is about 100%.
The probability of drawing a blue marble from a bag containing 18 marbles, of which 3 are blue, is calculated by dividing the number of blue marbles by the total number of marbles. Therefore, the probability is ( \frac{3}{18} ), which simplifies to ( \frac{1}{6} ). Thus, the probability of drawing a blue marble is approximately 0.167 or 16.7%.
19
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
100%
A bag of marbles contains 13 marbles. 5 Blue, 3 Yellow, 4 Green and 1 Red. Leave all answers as a ratio in lowest terms. 18 points On a single draw, what is the probability of drawing a yellow marble? What is the probability of not drawing a yellow marble? What are the odds in favor of drawing a blue marble? What is the probability of drawing a red or yellow marble? What is the probability of drawing a purple marble? If you had to bet on drawing a marble of a certain color what color would you not choose?
19
4 out of 25
3 in 10
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
20% (or 2 in 10 chance)
Yes, it certainly can if there is only one possible outcome. For instance, the probability of drawing a red ball from a bag containing nothing but red balls is equal to one.
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
Probability of drawing a heart: 1/4 Probability of drawing a club: 1/4 Probability of drawing a heart or a club: 1/4 + 1/4 = 2/4 = 1/2
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).