19
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
100%
19
4 out of 25
3 in 10
your probability would be 13/13. you would have a 100 percent chance of getting a green marble
20% (or 2 in 10 chance)
Yes, it certainly can if there is only one possible outcome. For instance, the probability of drawing a red ball from a bag containing nothing but red balls is equal to one.
Suppose probability of drawing a red marble is p. Then p = 2*(1 - p) that is p = 2 - 2p or p = 2/3 So 2/3 of the 24 marbles are red 24*(2/3) = 16 red marbles.
Probability of drawing a heart: 1/4 Probability of drawing a club: 1/4 Probability of drawing a heart or a club: 1/4 + 1/4 = 2/4 = 1/2
There are 9+6 = 15 checkers in the bag. 6 of them are red. 6 out of 15 are red. Drawing a red checker has a probability of P = 6/15 = 2/5 = 0.4 = 40% Since you replace the checker, the probability Q that red is drawn again remains 0.4. The probability of both events occurring (red drawn twice) equals the product of probabilities, PQ = (0.4)*(0.4) = 0.16.
Probability of not drawing an ace equals one minus the probability of drawing an ace. The probability of drawing an ace is 4/52 or 1/13. So the probability of not drawing an ace on one draw is 1 - 1/13 or 12/13 or 0.9231 (92.31%).
The answer depends on drawing a 9 from WHAT!