as 132 is an even number
at least one of the two numbers must also be even
12 + 11 = 23
12 x 11 = 132
3 prime numbers which have the sum of 132: 2 + 3 + 127 2 + 17 + 113
2 3 5 7 11 Sum: 28 Product: 2310
If the sum of 2 numbers is 25 and their product is 156, the 2 numbers would be 12 and 13.
113 + 19 = 132 109 + 23 = 132 103 + 29 = 132 101 + 31 = 132 89 + 43 = 132 79 + 53 = 132 73 + 59 = 132 71 + 61 = 132 So there are 8 pairs of prime numbers that sum to 132.
Any two odd numbers will have an odd product and an even sum.
11 and 12
3 prime numbers which have the sum of 132: 2 + 3 + 127 2 + 17 + 113
Sum of squares? Product?
How about: 127+5 = 132
The numbers are -134, -132 and -130.
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
find two positive numbers whose product is a maximum. 1.) the sum is s.
19
A "sum" is a process that involves at least two numbers, and a "product" is also a process that involves at least two numbers. Your question talks about a 'sum' and a 'product', so we expect to find at least four numbers to work with. But there are only two numbers in the whole question. So, to put it gently, we find the question to be somewhat deficient, and lacking an answer.
What's the question ? Is it to find what the two numbers are ? Since you know their average, you know what the sum of the two numbers is. It's double their average. Now you know their sum, and you know their product. Take the product, and list all of its factors. Find two of the factors that add up to the sum of the two numbers. Those are probably the two numbers you're looking for.
Two numbers have a product of 80 their sum is 24?
2 3 5 7 11 Sum: 28 Product: 2310