The numbers are 116, 118 and 120.
118
117, 118 and 119.
Thanks for sharing. The integers are 58 and 60.
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
There are two consecutive even integers. The numbers are 118 and 120.
The numbers are 116, 118 and 120.
121
118
117, 118 and 119.
Thanks for sharing. The integers are 58 and 60.
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
The GCF of consecutive integers is 1.
There are no sets of three consecutive numbers totaling 118.
To work this sort of problem out we need to divide the number given by the number of integers being sought (in that case two) 118 ÷ 2 = 59. So the two numbers will average 59 and they must be consecutive and even, that means that they must be 1 above and 1 below 59..... 58 and 60. 58 + 60 = 118
116 + 118 = 234. Answer is 118. Took 5 seconds to do.
The numbers are 28, 29, 30 and 31.Working X + (X+1) + (X+2) + (X+3) = 118 4X + 6 = 118 4X = 112 X = 112/ 4 X = 28 Therfore the consecutive numbers are 28, 29, 30 and 31. Check yourself.