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x + y = 16 so x = 16 - y

10y + x = 10x + y - 18

9y = 9x - 18 ie 9y = 144 - 9y - 18 ie 18y = 126: y = 7 so original number was 79

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What is the algorithm to reverse all the digits of an integer?

To reverse all the digits of an integer, you can use the following algorithm: Initialize a variable to store the reversed number. While the original number is greater than zero, extract the last digit using the modulus operator (%), append it to the reversed number by multiplying the current reversed number by 10 and adding the extracted digit. Then, remove the last digit from the original number by performing integer division by 10. Finally, handle any potential negative signs if needed.


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