Let lowest number be n. The larger numbers are n + 2 and n + 4.
So 4n2 = (n + 2)2 + (n + 4)2 + 12
= n2 + 4n + 4 + n2 + 8n + 16 + 12
= 2n2 + 12n + 32
So 4n2 - 2n2 - 12n - 32 = 0
ie 2n2 - 12n -32 = 0
which factorises as (2n - 16)(n + 2)
The positive solution is thus n = 16/2 = 8 and the other numbers are 10 & 12.
There are no such integers.
The integers are 10 and 11.
x+3 and x+4 would be consecutive integers.
-1
-10 and -11.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
There are no such integers.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
The integers are 10 and 11.
12 and 13.
The larger integer is 30. The smaller is 28.
x+3 and x+4 would be consecutive integers.
44 & 45
-1
-10 and -11.
Consecutive square numbers are the squares of consecutive integers. For example, if you take the integers 1, 2, and 3, their squares are 1² = 1, 2² = 4, and 3² = 9, making 1, 4, and 9 consecutive square numbers. These square numbers differ by an increasing odd number: 4 - 1 = 3 and 9 - 4 = 5. Thus, the pattern continues as you square larger consecutive integers.
4 and 6