-10 and -11.
55 and 57
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?
9 and 10 9 + 2(10) = 29
18, 20 and 22
27, 29
55 and 57
Nice little problem !Call the consecutive integers ' x ' and ' x+1 '.The sum is [ x + 2(x+1) ] = Ax + 2x + 2 = A3x + 2 = ASubtract 2 from each side:3x = A - 2Divide each side by 3:x = (A-2)/3 and that's the smaller of the two integers.The larger one is (x+1) = (A+1)/3
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
no one wants to know the answer. its freaking math
The sum of two consecutive integers can not be even unless both are even or both are odd.x+y=70y=4+2xx+(4+2x)=704+3x=703x=70-43x=66x=22y=70-22y=48The two numbers are 22 and 48. 22 is the smaller.
There are two consecutive odd numbers such that five times the smaller plus twice the greater is 25. What is the smaller number?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
They are (14, 15, 16).
9 and 10 9 + 2(10) = 29
18, 20 and 22
Let the two odd numbers be n and n+2, then : 2(n + 2) + 13 = 3n 2n + 4 + 13 = 3n n = 17 The smaller of the two odd numbers is 17 and the larger number is 19.