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Oh, isn't that a happy little math problem! To find the first integer, you can use a simple formula. Since the sum of 4 consecutive integers is 182, you can divide 182 by 4 to find the average value of the integers. Then, you can work backwards to find the first integer. Just remember, there are no mistakes in math, only happy little accidents!
What else can I help you with?
What are 4 consecutive integers of the sum of 182?
Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
What are the two consecutive numbers that equal 362?
The two consecutive even numbers are 180 and 182.
What Two consecutive numbers with product 182?
13 and 14
List 2 consecutive numbers that add up to 182?
184
Why is 360 not a square number?
It is not a perfect square because 182 = 324 and 192 = 361 Therefore, there is no integer which can be squared to equal 360.
Two consecutive integers for 182?
13 x 14 = 182
The product if two consecutive integers is 182?
13 x 14 = 182
Find two consecutive integers that have products of 182?
The integers are 13 and 14.
What are two consecutive integers that have a product of 182?
13 and 14
What are 2 consecutive numbers that are equal to 182?
There are two consecutive even integers: 90 and 92.
What is sum of three consecutive even integers that equals 546?
The integers are 180, 182 and 184.
Find two consecutive negative integers whose product is 182?
-13*-14 = 182
182 is the product of 2 consecutive integers but the answer is not unique?
The numbers are 13 and 14.
What are 4 consecutive integers of the sum of 182?
Let's represent the four consecutive integers as x, x+1, x+2, and x+3. The sum of these integers can be expressed as x + (x+1) + (x+2) + (x+3) = 4x + 6. We are given that this sum is equal to 182, so we can set up the equation 4x + 6 = 182. Solving for x, we find x = 44. Therefore, the four consecutive integers are 44, 45, 46, and 47.
Find two consecutive integers that have a product of 182?
13 and 14. Also negative 13 and negative 14.
What are two consecutive integers whose product is 168?
Yeah, those two integers don't exist 12 x 13 is 156 - too low the very next integers or too high 13 x 14 is 182 - too high if it helps 12 x 14 is 168, but these are not consecutive
What are two consecutive integers have a product of 182?
One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.
