2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
5(x^2 + y)
To find 2 times the sum of x and y, you first need to calculate the sum of x and y by adding the two variables together. Once you have the sum, you multiply it by 2 to get the final result. In mathematical terms, the expression for 2 times the sum of x and y can be written as 2(x + y).
x - y = x + (-y)
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
The sum of x and y decreased by their product is (x + y)- xy.
X+y
5(x^2 + y)
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
x - y = x + (-y)
2(x+y)=2x+2y
Sine sum identity: sin (x + y) = (sin x)(cos y) + (cos x)(sin y)Sine difference identity: sin (x - y) = (sin x)(cos y) - (cos x)(sin y)Cosine sum identity: cos (x + y) = (cos x)(cos y) - (sin x)(sin y)Cosine difference identity: cos (x - y) = (cos x)(cos y) + (sin x)(sin y)Tangent sum identity: tan (x + y) = [(tan x) + (tan y)]/[1 - (tan x)(tan y)]Tangent difference identity: tan (x - y) = [(tan x) - (tan y)]/[1 + (tan x)(tan y)]
Consider sum of two number to be x+y=6 and x/y=7. On substitution, it is found that x=4.42 and y=1.58.
x=5/y=5