(x+y)+3
The sum of x and y decreased by their product is (x + y)- xy.
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
This is a good exercise in building and solving a set of equations. Let X and Y be the two numbers. Then you are told their sum is 36, so write; X + Y = 36 Then you are told their difference is 24, so write; X - Y = 24 Now elliminate Y by adding the two equations; 2X = 60 and X = 30 . Now you can find Y by substituting this answer into either of the two original equations to get Y = 6.
(x+y)+3
x - (y + 2)
x*(y+z) = x*y + x*z This is the distributive property of multiplication over addition.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
x + y = 41, where x and y are unknown integers.
y = x +8 where x is the number
x+7=y
The sum of x and y decreased by their product is (x + y)- xy.
x+y
(x + y)/20
5(x^2 + y)