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20 * 19 * 18 * 17 = 116,280 ways

This is Permutation: nPr = n! / (n-r)!

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How many different ways can 4 students be chosen to serve on a committee from a group of 30 students?

One must first consider the number of ordered ways that 4 students may be chosen, and then divide that by the number of ways the four may have been ordered to create a number of distinct groups. For the orders, there are 30 choices for the first, 29 for the second, 28 for the third, and 27 for the fourth. However, there are a 4 ways within the four to pick the first, 3 ways for the second, 2 for the third, and 1 left for the fourth. The answer may be expressed by the following: 30 x 29 x 28 x 27 ______________ 1 x 2 x 3 x 4 which evaluates to 27,405 committees.


Is the second and the fourth finger has the same length?

Yes, the second and the fourth finger are the same length.


How many ways can a committee of 3 students be chosen from a total count of 1514 students?

The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864


How many ways can you line up 4 students out of a class of 20?

-- The first place can be any one of 20 students. For each of these, -- the second place can be any one of the remaining 19 students. For each of these, -- the third place can be any one of the remaining 18 students. For each of these, -- the fourth place can be any one of the remaining 17 students. So the four places can be assigned in any one of (20 x 19 x 18 x 17) = 116,280 ways.


How many ways can a committee of three be chosen from a total amount of 4463 students?

The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111

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Freshmen are first-year students in high school or college, sophomores are second-year students, and seniors are fourth-year students. Each term corresponds to a specific year of study within academic institutions.


How many different ways can 4 students be chosen to serve on a committee from a group of 30 students?

One must first consider the number of ordered ways that 4 students may be chosen, and then divide that by the number of ways the four may have been ordered to create a number of distinct groups. For the orders, there are 30 choices for the first, 29 for the second, 28 for the third, and 27 for the fourth. However, there are a 4 ways within the four to pick the first, 3 ways for the second, 2 for the third, and 1 left for the fourth. The answer may be expressed by the following: 30 x 29 x 28 x 27 ______________ 1 x 2 x 3 x 4 which evaluates to 27,405 committees.


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Is the second and the fourth finger has the same length?

Yes, the second and the fourth finger are the same length.


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