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-- The first place can be any one of 20 students. For each of these, -- the second place can be any one of the remaining 19 students. For each of these, -- the third place can be any one of the remaining 18 students. For each of these, -- the fourth place can be any one of the remaining 17 students. So the four places can be assigned in any one of (20 x 19 x 18 x 17) = 116,280 ways.
What else can I help you with?
In a class of 5 students how many ways could they be arranged to stand in a line?
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
How many ways can six students be arrange in a lunch line?
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
How many ways can a teacher select 5 students from a class of 23 students to create a bulletin board display?
Well, honey, to select 5 students from a class of 23, you're looking at a good old-fashioned combination problem. So, the number of ways a teacher can select 5 students from a class of 23 is 23 choose 5, which equals 3,359 ways. So, get those students ready to shine on that bulletin board!
How many different ways can an after-school club of 13 students line up?
The number of different ways 13 students can line up is calculated using the factorial of 13, denoted as 13!. This means multiplying all whole numbers from 1 to 13 together, which equals 6,227,020,800. Therefore, there are 6,227,020,800 different ways for the 13 students to line up.
How many ways to line 5 students up in a class of 20?
20*19*18*17*16 = 1860480 ways.
In how many ways can 7 students line up a a ticket booth?
There are 5040 ways.
How many different ways can 1 committee of 5 students be selected from a class of 25?
53,130 ways.
Is this a permutation In how many different ways could a committee of 5 students be chosen from a class of 25 students?
6,375,600
How many ways can an adviser chosen 4 students from a class of 12 if they are given a different task?
There are 11880 ways.
How many ways can a president and vice president be randomly selected from a class of 28 students?
They can be selected in 756 ways.
How many ways can 4 students stand in line?
4*3*2*1 = 24 ways.
In a class of 5 students how many ways could they be arranged to stand in a line?
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
How many ways can six students be arrange in a lunch line?
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
How many ways can seven students line up to buy concert tickets?
7
How many ways can a teacher select 5 students from a class of 23 students to create a bulletin board display?
Well, honey, to select 5 students from a class of 23, you're looking at a good old-fashioned combination problem. So, the number of ways a teacher can select 5 students from a class of 23 is 23 choose 5, which equals 3,359 ways. So, get those students ready to shine on that bulletin board!
