97, 98
Find two consecutive numbers with the value of 4160
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
The numbers are 103 and 104.
The numbers are 14 and 15.
The numbers are 64 and 65.
97 x 98 = 9506
sqrt(9506) = 97.50 So 97 and 98 are the two numbers.
There are two consecutive even numbers: 4,752 and 4,754.
As 9506 is even, at least one of its factors must be even - there are no two odd numbers (only) that will multiply together to get 9506. The factor pairs of 9506 are: 1 x 9506 2 x 4753 7 x 1358 14 x 679 49 x 194 97 x 98 97 and 98 are two consecutive numbers whose product is 9506.
Find two consecutive numbers with the value of 4160
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
two consecutive numbers with the product of 1722 = 41 & 42
23x24.
Yes.
They are 14 and 15.
The numbers are 103 and 104.