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Let's denote the two consecutive numbers as x and x+1. We know that their product is 9506, so we can set up the equation x(x+1) = 9506. By expanding the left side of the equation, we get x^2 + x = 9506. Rearranging the terms, we have x^2 + x - 9506 = 0. By solving this quadratic equation, we find that the consecutive numbers are 97 and 98.
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Find two consecutive numbers with a product of 9506?
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