If 2 taps fill 2/5 of the tank in 20 minutes then each tap fills 1/5 of the tank in that time.
3/5 of the tank is still to be filled.
One tap therefore takes 3/5÷ 1/5 x 20 = 60 minutes = 1 hour to fill the rest of the tank.
F1 fills one-eighth per minute, F1 & F2 together fill one-fifth per minute, so F2 is responsible for one-fifth less one-eighth ie three-fortieths per minute so F2 alone would take 40/3 ie 13 min 20 sec.
Since you didn't write the Tony's time, let find for how long Jim and Sue can fill the pool together. Jim can fill 1/2 of the pool in 15 minutes. Sue can fill 1/3 of the pool in 15 minutes. Together can fill 5/6 of the pool in 15 minutes (1/2 + 1/3). In how many minutes (let's say x minutes) they will fill 1/6 of the pool? Since it is left a small piece of the pool to fill out, it will take a few minutes to fill it. So we can form a proportion such as: (5/6)/(1/6) = 15/x 5/1 = 15/x cross multiply 5x = 15 divide both sides by 5 x = 3 It will take 3 minutes to fill 1/6 of the pool. So that together they will fill the pool in 18 minutes (15 + 3).
To find out how long it takes to fill 500 bottles, first determine the rate of filling. If 200 bottles take 12 minutes, then the rate is ( \frac{12 \text{ minutes}}{200 \text{ bottles}} = 0.06 ) minutes per bottle. For 500 bottles, it would take ( 500 \times 0.06 ) minutes, which equals 30 minutes. Thus, it will take 30 minutes to fill 500 bottles of soda.
It would take the too pipes 30 minutes to fill the tank when working together.This figure can be found in the following manner:Find the fill-speed of the first pipe50 minutes to fill 6000 Liters. 6000L/50m gives us 120L/m (liters-per-minute)6000 Liters in 75 minutes = 6000L/75m = 80L/mNext find the speed of the second pipeNow we combine the two rates (120+80), and we find that the pipes have a combined fill-speed of 200L/mFinally, we determine that it takes 30 minutes to fill the tank at 200L/m
A fills 1/20th per minute and B fills 1/60th per minute. After 10 minutes A has filled 10/20ths ie half, and B has filled 10/60ths ie 1/6. There is therefore 2/6 unfilled ie 20/60ths so B alone will complete the filling in 20 more minutes.
F1 fills one-eighth per minute, F1 & F2 together fill one-fifth per minute, so F2 is responsible for one-fifth less one-eighth ie three-fortieths per minute so F2 alone would take 40/3 ie 13 min 20 sec.
Wanda Sykes
In 15 minutes. Jim can fill 1/2 of the pool in 15 minutes, Sue can fill 1/3, and Tony can fill 1/6 of the pool in 15 minutes. Thus, together they can fill the pool in 15 minutes.
55 minutes
Since you didn't write the Tony's time, let find for how long Jim and Sue can fill the pool together. Jim can fill 1/2 of the pool in 15 minutes. Sue can fill 1/3 of the pool in 15 minutes. Together can fill 5/6 of the pool in 15 minutes (1/2 + 1/3). In how many minutes (let's say x minutes) they will fill 1/6 of the pool? Since it is left a small piece of the pool to fill out, it will take a few minutes to fill it. So we can form a proportion such as: (5/6)/(1/6) = 15/x 5/1 = 15/x cross multiply 5x = 15 divide both sides by 5 x = 3 It will take 3 minutes to fill 1/6 of the pool. So that together they will fill the pool in 18 minutes (15 + 3).
how many minutes are needed to fill a tank 166060.8 cubic inches
.50+.75+1.5=2.75/3=.91666666667=55/60 55 Minutes
base times height
To find out how long it takes to fill 500 bottles, first determine the rate of filling. If 200 bottles take 12 minutes, then the rate is ( \frac{12 \text{ minutes}}{200 \text{ bottles}} = 0.06 ) minutes per bottle. For 500 bottles, it would take ( 500 \times 0.06 ) minutes, which equals 30 minutes. Thus, it will take 30 minutes to fill 500 bottles of soda.
4.5 minutes
About 3 minutes! But if its a big tub about.......5 minutes.
1hour