Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).
Complete the square to find the transformation. -2(x-2)^2-4 the y value is -4. so the vertex is at (2,-4) OR Use the vertex formula: -b/2a a=-2 b=8 x=-8/(2)-2 x=2 Run 2 through the original equation: y=-(2)^2+8(2)-12 y=4
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
Given three vertices, the two that are the furthest apart lie at the ends of a diagonal. Reflect the square in this diagonal. The third vertex will be where the missing vertex should be.
Use a calculator.
Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).
Here is an example of how to find the vertex of y=(x+1)2 + 2 by graphing. First enter (x+1)2 + 2 into Y1 and graph it (press Y=, enter the equation, and then press GRAPH). You should be able to see the vertex (if not press ZOOM, then ZStandard to reset back to the standard viewing window.) You need to know if the vertex is a minimum or a maximum. In this case, it is a minimum. Press 2ND CALC (above TRACE) and select minimum. (You would select maximum if the vertex were a maximum. The calculator will ask for a left bound. Use the left arrow key to move the flashing start to the left of the vertex and then press ENTER. The calculator will then ask for a right bout. Move the flashing star to the right of the vertex and then press ENTER. The calculator will then ask for a guess. Move the flashing star close to the vertex (between the bounds you set) and pres ENTER. Then calculator will then display the coordinates of the vertex. In this case, it will say that x is -1 and y is 2.
15*1 to 15*66. Use your calculator to find them.15*1 to 15*66. Use your calculator to find them.15*1 to 15*66. Use your calculator to find them.15*1 to 15*66. Use your calculator to find them.
Complete the square to find the transformation. -2(x-2)^2-4 the y value is -4. so the vertex is at (2,-4) OR Use the vertex formula: -b/2a a=-2 b=8 x=-8/(2)-2 x=2 Run 2 through the original equation: y=-(2)^2+8(2)-12 y=4
use googe and type clockworks calculator
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
2x2-2 = -5x-1 2x2+5x-2+1 = 0 2x2+5x-1 = 0 Use the quadratic equation formula to find the values of x: x = 0.1861406616 or x = -2.686140662
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
Get out calculator and divide the number by seven. If you can use a computer, use the calculator on your computer.
You can go to irs.gov and use your debt repayment calculator. You can also go to your banking institution and have them use their repayment calculator as well
Given three vertices, the two that are the furthest apart lie at the ends of a diagonal. Reflect the square in this diagonal. The third vertex will be where the missing vertex should be.
The answer is 35,295. PS: You can use a calculator to find out the answer.