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How do you find the vertex of 2x2 plus 4 plus 1?
2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
Where is the vertex of the graph of y equals x2 plus 2x plus 5 located?
We need to complete the square to find the vertex of this parabola. X^2 + 2X + 5 = 0 X^2 + 2X = -5 halve the coefficient of the linear term ( 2X ) and square it perfectly and add to other side (X + 1)^2 = -5 + 1 (X + 1)^2 = -4 (X + 1)^2 + 4 = 0 Vertex is.... X = -1 Y = 4
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
What is the process to graph quardratic equations?
If you are using a calculator just plug it in and hit graph. If you are doing it by hand, start with making a X-Y Table. Plug in X values into the equation to get a Y value out. Plot about 5 points on the graph to get a basic look at the parabola. To get the right the values, you want to start with the vertex and go out from there. To start, you need to find the axis of symmetry (-b/2a) [From the basic equation of ax squared +bx + c] That is the X Value for the vertex. Plug that in to find the Y Value for the vertex. The more points you find the more accurate the graph but normally 5 is enough (vertex and two on left and right)
