x2 * -3x = -3x3
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
A binomial
X2 A number to the second power is squared.
x2-9x = x(x-9)
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
x2 * -3x = -3x3
7
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
x2+9x-36 = (x-3)(x+12) when factored
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2-9x+18 = (x-3)(x-6) when factorised
x3 - 3x2 - 9x + 27 = x2(x - 3) - 9(x - 3) = (x - 3)(x2 - 9) = (x - 3)(x - 3)(x + 3)
No.
A binomial