-9(x + 8)
I hope you mean x3+2x2-9x+18. Treat the equation like two equations: x3+2x2 and 9x+18. Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2). Now, the whole equation. x2(x+2)-9(x+2). Factor out (x+2), so (x+2)(x2-9). (x2-9) factors into (x+3)(x-3). So, (x+2)(x+3)(x-3) is the complete factorization. Hope this helps.
5x2 + 9x + 13 has no real factors.
3x2 - 9x - 912 = 3(x2 - 3x - 304) = 3(x - 19)(x + 16).
4
x2-9x can be factored by taking x out of each term x(x-9)
x2 - 9x + 8 = (x-1)(x-8)
-9(x + 8)
(x + 12)(x - 3)
(x+1)(x+8)
9x2 + 8x - 1 = (9x - 1)(x + 1)
(9x + 8)(9x - 8)
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
(2x+3)(x+3)
x2-9x+8=0 has two solutions:x = 8x = 1
3(2x - 3)(x + 3)
- 8x2