0
Add your answer:
Earn +20 pts
What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
What are the factors of the trinomial n plus 11n plus 30?
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
Codings for coprime number in c?
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
What is the additive inverse for -n2-7?
-5
What is the hybridization of N in N2?
The hybridization of N i n N2 is sp.
What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?
If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared
What are the factors of the trinomial n plus 11n plus 30?
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
What is the pmf of trinomial distribution?
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
What is the oxidation number for N2?
0 in N2
What is oxidation number for N2?
0 in N2
What is n2 in math?
n x n = n2
Codings for coprime number in c?
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
How do you find the number of moles of nitrogen gas in 3.2L?
1 mole N2 = 22.4L 3.2L N2 x 1mol N2/22.4L = 0.14 mole N2
How many sweets were originally in the bag after the probability Tommy Tucker eating 2 red ones one after another was 1 over 8 when the bag contained 6 red and other assorted sweets showing work?
Let the number of sweets be n and use the rules of probability:- If: 6/n times 5/n-1 = 1/8 Then: 30/n2-n = 1/8 Multiplying both sides by n2-n: 30 = n2-n/8 Multiplying both sides by 8: 240 = n2-n Subtracting both sides by 240: 0 = n2-n-240 Solving the above quadratic equation: n = 16 or n = -15 Therefore it follows: n = 16 sweets Note that n2 means n squared
How do you balance this equation N2 plus H2 to NH3 plus N2?
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
What is N2H4------NH3 plus N2 in a balanced equation?
The balanced equation for the reaction N2H4 → NH3 + N2 is: 3N2H4 → 4NH3 + N2
