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What is (30) of ( n-2)?

Updated: 9/27/2023
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Venie Mendoza

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Q: What is (30) of ( n-2)?
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What is the value of n when 6 over n times 5 over n-1 equals 1 over 3 showing all work?

If you mean: 6/n times 5/n-1 = 1/3 Then: 30/n2-n = 1/3 Multiplying both sides by n2-n: 30 = n2-n/3 Multiplying both sides by 3: 90 = n2-n Subtracting 90 from both sides: 0 = n2-n-90 or n2-n-90 = 0 Solving the above quadratic equation: n = -9 or n =10 If n is of a material value its more likely to be 10 Note that n2 means n squared


What are the factors of the trinomial n plus 11n plus 30?

Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).


Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?

n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.


How do you add n squared plus n squared?

n2 + n2 = 2 n2


What is the pmf of trinomial distribution?

P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n


What is the oxidation number for N2?

0 in N2


What is oxidation number for N2?

0 in N2


How many sweets were originally in the bag after the probability Tommy Tucker eating 2 red ones one after another was 1 over 8 when the bag contained 6 red and other assorted sweets showing work?

Let the number of sweets be n and use the rules of probability:- If: 6/n times 5/n-1 = 1/8 Then: 30/n2-n = 1/8 Multiplying both sides by n2-n: 30 = n2-n/8 Multiplying both sides by 8: 240 = n2-n Subtracting both sides by 240: 0 = n2-n-240 Solving the above quadratic equation: n = 16 or n = -15 Therefore it follows: n = 16 sweets Note that n2 means n squared


Codings for coprime number in c?

#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }


What is n2 in math?

n x n = n2


How do you find the number of moles of nitrogen gas in 3.2L?

1 mole N2 = 22.4L 3.2L N2 x 1mol N2/22.4L = 0.14 mole N2


What volume is occupied by 20. 0 g of nitrogen (N2) gas at 30 degree C. and 800 mmHg?

1 mol N2 = 28g 30C = 303K At STP, 1mol * 273K is proportional 24L * 760torr. (PV = nRT) Then we do a little bit of stoichiometry... 10g * 1mol/28g * 24L*760torr/(1mol*273K) * 303K * xL/750torr = 9.6402 L 10.0g of N2 at 30C and 750torr should occupy 9.6402L