vbh
(x + 10)(x + 3)
32
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
Since 30 is positive and the sum is negative, both factors must be negative. Let's just look for pairs of factors of 30: 30 = 1x30 = 2x15 = 3x10 = 5x6. None of these factor pairs add to 30, so you can't solve this over the integers. You are probably trying to solve a quadratic equation like x2 -12x +30 = 0. Since you can't find two binomial factors for the trinomial, you will have to use the quadratic formula to solve the equation. Haven't got that far in your algebra class? OK, just say it can't be done.
vbh
(x + 10)(x + 3)
(x - 10)(x - 3)
32
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
X^2 - 13X + 30 = 0 (X-3)(X-10) easy inspection problem
x2 - 13 + 30 = x2 + 17, which has no real factors.
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
30 + 30 + 30 + 30 + 30 + 30 = 180
Since 30 is positive and the sum is negative, both factors must be negative. Let's just look for pairs of factors of 30: 30 = 1x30 = 2x15 = 3x10 = 5x6. None of these factor pairs add to 30, so you can't solve this over the integers. You are probably trying to solve a quadratic equation like x2 -12x +30 = 0. Since you can't find two binomial factors for the trinomial, you will have to use the quadratic formula to solve the equation. Haven't got that far in your algebra class? OK, just say it can't be done.
x^2 - x + 30 doesn't have rational factors. If that was - 30, it would factor to (x - 6)(x + 5)
4!