The three consecutive numbers whose sum and product are the same are 1, 2, and 3.
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
150
1 2 and 3. 1+2+3=6 1x2x3=6
No. Take 12 for example. 1+2=3 but 1x2 doesn't equal 3, it equals 2.
1, 2, 3, 4
The three consecutive numbers whose sum and product are the same are 1, 2, and 3.
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
A number is divisible by 3 if the sum of its digits is divisible by 3.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
150
The sum of the digits is a multiple of 3
1 2 and 3
Factor 12 = 2x2x3 There's no combination for -12 as a product and -3 as a sum at the same time.