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One recursive pattern starting with 4 and 7 could be the Fibonacci-like sequence where each term is the sum of the two preceding ones: 4, 7, 11, 18, 29, and so on. Another pattern could involve alternating addition and subtraction; for example, starting with 4, then adding 3 to get 7, then subtracting 1 to get 6, and repeating this with the results: 4, 7, 6, 9, 8, 11, etc.
What else can I help you with?
How many recursive patterns can you find with 4 plus 7 as the first 2 terms?
Infinitely many. For example: Un+1 = Un + 3 or Un+1 = 2*Un - 1 or Un+1 = 3*Un - 5 or, more generally, Un+1 = k*Un + 7 - 4*k where k is any number. Each one of them will be different from the third term onwards. These are linear patterns. There are quadratic and other recursive relationships.
What is the recursive patterns for 4 and 7 as the first 2 terms?
To establish a recursive pattern starting with 4 and 7 as the first two terms, we can define the sequence such that each subsequent term is the sum of the previous two terms. Thus, the recursive formula would be ( a_n = a_{n-1} + a_{n-2} ) with initial conditions ( a_1 = 4 ) and ( a_2 = 7 ). The next terms would be ( a_3 = 4 + 7 = 11 ), ( a_4 = 7 + 11 = 18 ), and so on. This creates a sequence: 4, 7, 11, 18, ...
What 4 recursive patterns can you make starting with 4 and 7?
Starting with the numbers 4 and 7, you can create the following recursive patterns: Addition Pattern: Each term is the sum of the previous two terms, starting with 4 and 7 (e.g., 4, 7, 11, 18, 29, ...). Multiplication Pattern: Multiply the previous two terms to get the next one (e.g., 4, 7, 28, 196, ...). Alternating Addition/Subtraction Pattern: Alternate adding and subtracting the original numbers (e.g., 4, 7, 3, 10, 6, ...). Doubling Pattern: Start with 4, then double it, followed by adding 7 to the previous term (e.g., 4, 8, 15, 30, ...).
Is 1-4-9-16-25-36 a recursive pattern?
no it is not a recursive pattern because it isn't equal numbers.
What is the recursive formula for 1 4 13 40 121?
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
How many different recursive patterns can you find with 4 and 7 as the first 2 terms?
there are 4 different ways you can do it
What is the recursive definition of 8 4 2 1?
8/4/2=1
How many recursive patterns can you find with 4 plus 7 as the first 2 terms?
Infinitely many. For example: Un+1 = Un + 3 or Un+1 = 2*Un - 1 or Un+1 = 3*Un - 5 or, more generally, Un+1 = k*Un + 7 - 4*k where k is any number. Each one of them will be different from the third term onwards. These are linear patterns. There are quadratic and other recursive relationships.
Is 4 9 19 39 79 159 recursive?
no it is not recursive
What 4 recursive patterns can you make starting with 4 and 7?
Starting with the numbers 4 and 7, you can create the following recursive patterns: Addition Pattern: Each term is the sum of the previous two terms, starting with 4 and 7 (e.g., 4, 7, 11, 18, 29, ...). Multiplication Pattern: Multiply the previous two terms to get the next one (e.g., 4, 7, 28, 196, ...). Alternating Addition/Subtraction Pattern: Alternate adding and subtracting the original numbers (e.g., 4, 7, 3, 10, 6, ...). Doubling Pattern: Start with 4, then double it, followed by adding 7 to the previous term (e.g., 4, 8, 15, 30, ...).
What is the recursive formula for 2 1 3 4 7 11?
It look like a Fibonacci sequence seeded by t1 = 2 and t2 = 1. After that the recursive formula is simply tn+1 = tn-1 + tn.
Is 1-4-9-16-25-36 a recursive pattern?
no it is not a recursive pattern because it isn't equal numbers.
What is the recursive formula for 1 4 13 40 121?
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
How can a recursive pattern go from 3 to 4 to 6 to 10 then 18?
t(1) = 3 t(n) = t(n-1) + 2(n-2) for n = 2, 3, 4, ...
What is the recursive formula for 64 to 16 to 4 to 1?
x_n+1 = x_n / 4
What is the recursive formula for -14 -8 -2 4 10?
t(n+1) = t(n) + 6 t(1) = -14
Which represents the first three terms of the sequence a1 2 and an 4(an-1)2?
Becasue the browser used by this site is unable to display most mathematical notation, this may not be the correct recursive formula, but:if a(1) = 2 and a(n) = 4*a(n-1)^2 then then a(2) = 4*2^2 =4*4 =16 and a(3) = 4*4^2 = 4*16 = 64
