There are 210 of them:
{1,2,3,4,5,6}, {1,2,3,4,5,7}, (1,2,3,4,5,8}, {1,2,3,4,5,9}, {1,2,3,4,5,10},
{1,2,3,4,6,7}, {1,2,3,4,6,8}, (1,2,3,4,6,9}, {1,2,3,4,6,10},
{1,2,3,4,7,8}, {1,2,3,4,7,9}, (1,2,3,4,7,10},
...
{1,3,4,5,6,7}, {1,3,4,5,6,8} and so on.
...
{2,3,4,5,6,7} etc
You can fill in the gaps and work out the rest.
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about 1,0000000000000
Assuming each "digit" actually has 10 different states, there are one million combinations possible in a six-digit combination lock. However, many combination lock designs actually have fewer than 10 different states per "digit", resulting in far fewer actual combinations on such locks.
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
it's 610, which is 60,466,176. Since each digit spot could be anything 0-9 there are 10 numbers to try for each digit, making it 610.
That depends on how many of the digits are repeated. If no digits are repeated, you have 9 choices for the first digit, 8 choices for the second, etc.; for a total of 9 x 8 x 7 x 6 x 5 x 4.