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There are 10 numbers 0,1,2,3,4,5,6,7,8,9 in all. Case 1: assuming that the numbers can repeat. The first digit can be chosen in 9 ways (exclude 0). The second in 10 ways(include 0) and so on. Total number of combinations is 9 x 10^7 (that is 9 times 10 to the power 7) ways. Case 2: assuming that the numbers cannot repeat. The first digit in 9 ways, the second digit in 9 ways, the 3rd in 8 ways, the 4th in 7 ways and so on. Total number of permuations is 9 x 9 x 8 x 7 x 6 x 5 x 4 x 3 =1632960 ways
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What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
What are every possible 10 digit combinations of the numbers 0 through 9?
There is only one combination since the order of the numbers in a combination does not matter.
What is a list of 5 digit combinations starting with a 3 and numbers can be repeated?
The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .
How many 5 digit combinations are possible using 8 specific non repeting numbers?
it depends on which 8 numbers your talking about
How many 10 digit combinations are there for the numbers 0 through 9?
Exactly 3,628,800, or 10!.
