110 | 121 | 132 | 143 | 154 | 165 | 176 | 187 | 198 |
209 | 220 | 231 | 242 | 253 | 264 | 275 | 286 | 297 |
308 | 319 | 330 | 341 | 352 | 363 | 374 | 385 | 396 |
407 | 418 | 429 | 440 | 451 | 462 | 473 | 484 | 495 |
506 | 517 | 528 | 539 | 550 | 561 | 572 | 583 | 594 |
605 | 616 | 627 | 638 | 649 | 660 | 671 | 682 | 693 |
704 | 715 | 726 | 737 | 748 | 759 | 770 | 781 | 792 |
803 | 814 | 825 | 836 | 847 | 858 | 869 | 880 | 891 |
902 | 913 | 924 | 935 | 946 | 957 | 968 | 979 | 990 |
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
The digit appears eleven time from 1 to 100.
3
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
100, 110 and 120 are 3 digit multiplies of 10.
Multiples of 30 from 120 to 990
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
There are 49 3-digit numbers - from 108 to 990 inclusive.
All integers have an infinite amount of multiples.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
99
50 of them.
60 numbers
The digit appears eleven time from 1 to 100.
-3
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers