No, 11 is the only palindromic prime with an even number of digits.
Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.
-11
Yes, because the sequence of digits is the same when read either forward or backward. (The spacing between the digits is irrelevant.)
1661 is a palindromic number.
a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)
No, 11 is the only palindromic prime with an even number of digits.
656
To be a 3 digit palindromic number, it must be of the form aba.I assume that a 3 digit number must be at least 100 (so that 020 for example does not count as a 3 digit number):a can be any of the nine digits 1-9;for each of these b can be any of the ten digits 0-9Thus there are 9 x 10 = 90 three digit palindromic numbers.
11
137?
Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.
-11
Yes, because the sequence of digits is the same when read either forward or backward. (The spacing between the digits is irrelevant.)
1661 is a palindromic number.
A palindromic number is a number whose digits, with decimal representation usually assumed, are the same read backwards, for example, 58285.
Off the top of my head, 1001 is the answer. Check it out and see . . . _________ 1001 is not prime. 7 X 143 equals 1001. There is 11, which is prime and which has 2 digits.