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What IS the probability of drawing an ace or a ten from a standard deck of cards?
In a deck of 52 cards, there are 4 chances to get an ace and 4 chances to get a ten so there are 8 chances to get an ace or a ten So the probability is 8/52=2/13=0.15
What is the probability of rolling a 3 or 5 on a die?
a 2 out of 6 probability
What is the probability of getting a number greater than four when rolling a dice?
When you throw a dice there is always 6 chances of getting a number; therefore the numbers greater that 4 are: 5 and 6 (2 options) in total there will be 2/6 chances will simplifies to 1/3
If you roll two fair dice what is the probability a three or six will appear?
Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.
What is the probability of getting a number greater than or equal to 2 when rolling a number cube numbered 1 to 6?
Probability is a ratio written as the number of desired outcomes divided by the number of possible outcomes. On a six-sided number cube, there are 5 chances of getting a number greater than or equal to 2 (2,3,4,5,6) and 6 possible outcomes (1,2,3,4,5,6) so your probability would be 5/6.
What does 5 to 4 Odds ratio mean?
It means that for every 5 chances in favor, there are 4 chances against - same as a probability of 5/9.It means that for every 5 chances in favor, there are 4 chances against - same as a probability of 5/9.It means that for every 5 chances in favor, there are 4 chances against - same as a probability of 5/9.It means that for every 5 chances in favor, there are 4 chances against - same as a probability of 5/9.
If you had 2 dice what is the probability of rolling a 4?
4 out of 12 chances if each dice had 6 sides. 2 out of 6 chances to simplify it.
What is the probability of drawing a 2 in a deck of cards?
7.7% or 4 chances out of 52.
If you roll a die what is the probability of rolling a prime number?
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
The probability that fewer than 8 out of 10?
To get more than 8 one needs to get 9 or 10 so there are 2/10 chances The probability to get less than 8 is the opposite probability to the one before so it's 1-2/10 = 8/10 = 4/5 = 0.8
Chances of rolling an 11 on a pair of dice?
Total different rolls are 36 (6x6) Ways to roll an 11 is 2 (5/6 and 6/5) Probability = number_of_rolls_of_success/total_number_of_rolls = 2/36 = 1/18
What is the probability of throwing 2 dice so that you have a total score of 5?
When you throw 2 6-sided dice, there are 36 ways they can come up. Of those, 4 (1 and 4, 2 and 3, 3 and 2, 4 and 1) total 5. So the probability is 4 chances in 36, or 1 in 9 (1/9 = 0.11111...)
What is the probability that the a dice 2 is drawn if the two dice total is 5?
The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.
What is the probability of not rolling the difference of1?
Assuming that by a difference of 1 you mean rolling a pair (2) of dice and then subtracting the two numbers that you get individually on each die. Well there are 36 total possibilities. To get a difference of 1 you need a 6&5, 5&4, 4&3, 3&2, or 2&1. That represents 10 chances. not getting this is 36-10 = 26 chances. So the probability = 28 / 36 = 7/9.
A pair of dice is rolled what is the probability of getting a sum of 5?
since rolling a dice can give you 36 possible combinations, there are 1/9 chances that you will get a sum of 5. 1+4 2+3 3+2 4+1 the 4 equations above will produce a sum of 5 so,the probability is 4/36, or 1/9.
What is the probabilty that a coin will land on heads if flipped 8 times?
This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.
What is the mathematical chances that something will occur?
probability
