To get more than 8 one needs to get 9 or 10 so there are 2/10 chances
The probability to get less than 8 is the opposite probability to the one before
so it's 1-2/10 = 8/10 = 4/5 = 0.8
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The probability is 3/8.The probability is 3/8.The probability is 3/8.The probability is 3/8.
I'm assuming that a "1-8 spinner" is similar to an eight-sided die, so the probability of spinning a 10 is zero. When throwing dice, or flipping a coin, etc., each outcome is independent. That is, it's not influenced by the previous outcome(s). So if you get three 8s in a row then the probability of getting an 8 on the fourth throw remains at 1/8. The probability of an 8 on each and every throw is always 1/8.
If 10 coins are tossed, you could get 4 heads and 6 tails, 3 heads and 7 tails, 2 heads and 1 tail, 0 heads and 10 tails all giving fewer heads than tails. Using the binomial distribution , P(4 heads) = 10C4 (.5)^4 (.5)^6 = 0.205078. P(3 heads) = 10C3 (.5)^3 (.5)^7 = 0.117188 P(2 heads) = 10C2 (.5)^2 (.5)^8 = 0.043945 P(1 heads) = 10C1 (.5)^1 (.5)^9 = 0.009766 P(0 heads) =(.5)^10 = 0.000977 Adding all of these probabilities, we have P(fewer heads than tails)= 0.376953
If it is a fair spinner, then 3/8
It is 0.0547