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graph x+4<5
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
graph x+4<5
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
Very Carefully :)
"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
Neither x-1 nor x4 is an equation or an inequality. There is, therefore, nothing to graph anything.
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
Through signs of inequality Solve each inequality Graph the solution? 2(m-3)+7<21 4(n-2)-6>18 9(x+2)>9(-3)
if you have y <= f(x), then graph the function y = f(x) with a solid line, then shade everything below that graph.
The graph of the inequality ( X + 7 ) < 13 is the entire infinite half of the x-y plane to the left of the vertical line ( X = 6 ), but not including the line itself.
y -x - 2 is not an equation (nor an inequality) and so there is no way to graph it.
x=9