999 ÷ 7 = 142 remainder 5
142, 284, 426, 568, 710, 852, 994, . . .
The greatest common multiple of any set of integers is infinite.
There is no "most common multiple". To find all common multiples, you start by finding the least common multiple. All other common multiples are multiples of this least common multiple.
Each common multiple of 9 and 10 occurs exactly once (in the list of common multiples), so there is no common multiple that occurs the most. All common multiples of 9 and 10 are the multiples of their least common multiple which is 90.
The common multiples of 142 and 148 are 10,508, 21,016, 31,524, and so on.
999 ÷ 7 = 142 remainder 5
142*3 = 426
There are 30 multiples of 30 between 100 and 999.
142, 284, 426, 568, 710, 852, 994, . . .
Of course, the first multiple is 1 x 999 = 999. The next three multiples (multiplying by 2, 3 & 4) are: 1998, 2997, and 3996.
71, 142, 213 and so on.
142 999-1= 998 998/7 = 142.5714286 not 143, so 7 goes into 998 142 times evenly. This answer brought to you by the Casio FX-115ES
There are 179 multiples of 5 between 101 and 999. 101 ÷ 5 = 201/5 → first multiple of 5 ≥ 101 is 21 x 5 999 ÷ 5 = 1994/5 → last multiple of 5 ≤ 999 is 199 x 5 → number of multiples of 5 between 101 and 999 is 199 - 21 + 1 = 179.
999/3there are 333 multiples of 3
They are all multiples.
109 whole numbers greater than 9 and less than 999 are multiples of 9