142*3 = 426
The sum of the first 10 multiples of 3 is 165.
The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750Depending upon the interpretation of "of 3 and 5", the answer is one of:The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.
975
The common multiples of 142 and 148 are 10,508, 21,016, 31,524, and so on.
142, 284, 426, 568, 710, 852, 994, . . .
There are no two consecutive whole numbers that sum to 142.With two consecutive whole numbers, one is even and the other odd, and their sum will be odd, but 142 is even.Two consecutive even numbers that sum to 142 are 70 and 72.
27
-3
Sum_ap = ½ × number_of_terms × (first_term + last_term) For the first 88 multiples of three: number_of_terms = 88 first_term = 1 × 3 = 3 last_term = 88 × 3 = 264 → Sum = ½ × 88 × (3 + 264) = 44 × 267 = 11748
5 + 10+15+20=50 ans
factoring 142=2*71 999=3*3*3*37 no common factor so common multiple is 142*999=141,858 other mutliple woudl jsut be twice or three times or four thimes etc 141,858
10+20+30 = 60