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Earn +20 ptsQ: What are the dimensions of a rectangle with a perimeter of 52 feet?
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The width of a rectangle is 12 cm shorter than the length The perimeter is at least 52 cm What are the smallest possible dimensions of the rectangle?
7 x 19 cm
If a bedroom floor is a rectangle that is 16 feet wide the perimeter is 52 feet wide what is the area?
160 feet squared52-(16*2)= 2020/2=1010*16=160
How long is the diagonal of a rectangle with the dimensions of 6 feet x 4 foot?
Use Pythagoras' theorem: 62+42 = 52 and the square root of this is 7.211102551 Answer: 7.211102551 units
The length of a rectangle is fixed at 24 cm what widths will mame the perimeter greater than 100cm?
P (perimeter of a rectangle) = 2*l+2*w 2*24+2*w > 100 2*w > 52 w > 26 Any width greater than 26cm will cause the perimeter to be greater than 100cm.
If a rectangle has a perameter of 52cm and width of 12cm what is the length?
Perimeter of a rectangle = 2 x length + 2 x width. 52 = 2l + 2 x 12 = 2l + 24 (Where l is the length) 2l = 52 - 24 = 28 length = 28/2 = 14 cm
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