x2 = 4 - 7x
x2 + 7x - 4 = 0
Using the quadratic formula, x = 1/2*{-7 ± sqrt[72 - 4*1*(-4)]}
= 1/2*{-7 ± sqrt[49 + 16]}
= 1/2*{-7 ± sqrt[65]}
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2-7x-18 (x-9) (x+2) x=9 x=-2 X= either 9 or -2
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
Did you get the question from sevenstar academy, Algebra.
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
Do you mean the following? x2 = 4 - 7x If so, then: x2 + 7x = 4 x2 + 7x + 49/4 = 4 + 49/4 (x + 7/2)2 = 65/4 x + 7/2 = ±√65 / 2 x = (-7 ± √65) / 2 So x is equal to (-7 - √65) / 2 and (-7 + √65) / 2
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
-3
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
x2 × 7x = 7x3