x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2 - 11x + 24 = (x - 3)(x - 8)
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
This is the equation we want to factorize: x2 - 11x + 18 And there are two answers (the numbers are the same, but +/- signs are inverted): 1. (x - 2)(x - 9) = x2 - 9x - 2x -(-18) = x2 - 11x + 18 2. (-x + 2)(-x +9) = x2 -9x -2x + 18 = x2 - 11x + 18
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2 - 11x + 24 = (x - 3)(x - 8)
x2 -11x-12= (x-12)(x+1)
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
21
x2 - 13 + 30 = x2 + 17, which has no real factors.
x^2 + 11x + 6 has no rational zeros.
x(6x - 11)
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.