The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)
You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2 - 11x + 24 = (x - 3)(x - 8)
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
This is the equation we want to factorize: x2 - 11x + 18 And there are two answers (the numbers are the same, but +/- signs are inverted): 1. (x - 2)(x - 9) = x2 - 9x - 2x -(-18) = x2 - 11x + 18 2. (-x + 2)(-x +9) = x2 -9x -2x + 18 = x2 - 11x + 18
It is: x^2 +11x +24 = (x+8)(x+3) when factored
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2 - 11x + 24 = (x - 3)(x - 8)
x2 -11x-12= (x-12)(x+1)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
X2 -11x +10=(x - 1 )(x - 10)
x^3 - 121x
21
x2 - 13 + 30 = x2 + 17, which has no real factors.
x^2 + 11x + 6 has no rational zeros.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.