2500, 100n2
Restate the question: what are the 5th and nth term of (10n)2?
If this is not your question, please clarify and resubmit the question.
Assuming the first term is when n=1, then the 5th term is (10x5)2 = (50)2 =2500.
The nth term would be just (10n)2, although you could expand and simplify to get (102)(n2) = 100n2.
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
(Term)n = 59 - 2n
nth term Tn = arn-1 a = first term r = common factor
IT is A.P. Arithmetic progressionFormula to solven th term = First_term + ( n - 1)*difference_between_two_non=9first term=7difference_between_two_no = nth_term - (n-1)th_term = 5-7 = 3-5 =1-3 = -2nth term = 7+8*(-2) = -9Another Answer:-The nth term = 9-2n
The sequence has a difference of 10, so the nth term starts with 10n. Then to get to -8 from 10 you need to subtract 18. So the nth term is 10n - 18.
If you meant: 2 12 22 32 then the nth term = 10n-8
1 4 9 is a series of squared numbers. The nth term is [ n squared ]
It is: 10n-7 and so the next term is 43
10n + 1
15(1)
nth term is n squared plus three
t(n) = 6 + 8n
t(n) = t(n - 1) + (10n - 9)
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
t(3) = 10 - 32 = 1
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50