taking the 1st term as n=1
the 2nd term as n= 2 etc
then the first 5 terms of 16-3n are :
1st : 16-3 = 13
2nd : 16-6 = 10
3rd : 16-9 = 7
4th: 16-12 = 4
5th : 16-15 = 1
hope this helps
8
The first, second, third, fourth, and fifth terms of 3n - 7 are as follows:1: -42: -13: 24: 55: 8
5, 8, 11, 14 and 17.
if n is your number, then 3n - 5 = 16, ie 3n = 21 ie n = 7.
To simplify the expression (-3(6n - 5) + 3n), first distribute (-3) inside the parentheses: (-3 \cdot 6n + 15 + 3n = -18n + 15 + 3n = -15n + 15). Thus, the simplified expression is (-15n + 15).
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
8
The expression (3n + 1) represents a sequence where (n) is a positive integer. The first five terms can be found by substituting (n) with the values 1, 2, 3, 4, and 5. The first five terms are: For (n=1): (3(1) + 1 = 4) For (n=2): (3(2) + 1 = 7) For (n=3): (3(3) + 1 = 10) For (n=4): (3(4) + 1 = 13) For (n=5): (3(5) + 1 = 16) Thus, the first five terms are 4, 7, 10, 13, and 16.
5
The first, second, third, fourth, and fifth terms of 3n - 7 are as follows:1: -42: -13: 24: 55: 8
5, 8, 11, 14 and 17.
if n is your number, then 3n - 5 = 16, ie 3n = 21 ie n = 7.
3n -5 = 19 3n = 19+5 3n = 24 n = 8
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
If that's +25, that factors to (3n - 5)(3n - 5) or (3n - 5)2
To simplify the expression (-3(6n - 5) + 3n), first distribute (-3) inside the parentheses: (-3 \cdot 6n + 15 + 3n = -18n + 15 + 3n = -15n + 15). Thus, the simplified expression is (-15n + 15).
To find the first 5 terms, plug 1, 2, 3, 4 and 5 in for n:3*1-3 = 03*2-3 = 33*3-3 = 63*4-3 = 93*5-3 = 12The first five terms are 0, 3, 6, 9 and 12.