Number Term
1 1
2 4
3 7
4 10
5 13
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
5
10,11,12,13,14 or 8,10,12,14,16
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
(3n+2)(n+1)
If that is + 192 then divide all terms by 3 and it is (x+8)(x+8) when factored
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
so 3n2 = 15 ie n2 = 5 so n = sqrt 5
7
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
2,1,0 is th sequence of its terms
3
5
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.
Formula: (Hg2)3N2
2NaN ---> 2Na + 3N2