There are 256 of them.
You can get a list of them like this:
-- Take a very long piece of paper.
-- Write down all the numbers from zero to 9,999 . . . that's ten thousand numbers.
-- Cross out all the numbers on the list that have a 3, 4, 5, 6, 7, or 8 in them.
-- The 256 numbers you have left are the answer to your question.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
9000
∞ \ Infinite
1
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are 45 combinations.
9000
7
∞ \ Infinite
1
10P4 = 5040
9999
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
The number of combinations of 7 numbers from 10 is 10C7 = 10*9*8/(3*2*1) = 120