I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
No.
The odds of rolling 6 out of 2 consecutive dice is 100/25.
1 in 12
About 1.5% The odds of rolling a 7 on any particular throw is 1/6. (There are six ways you can roll a seven: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), out of 36 possible outcomes.) Therefore, the odds that you don't roll a 7 on a particular roll is 5/6. The odds that you don't roll a 7 in 23 rolls is: (5/6)^23, or approximately .015=1.5%
I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
The odds of rolling a 7 are 1/6. The odds of rolling two in a row are 1/36. The odds of rolling an 11 are 1/18. The odds of rolling two in a row are 1/324. The odds of rolling doubles are 1/6. The odds of rolling double twice in a row are 1/36.
No.
The odds of rolling 6 out of 2 consecutive dice is 100/25.
Odds of rolling ONE six - 6:1 Odds of rolling TWO sixes - 36:1 Odds of rolling two sixes, SIX times - 216:1
1 in 12
1/6 x 1/6 x 1/6 = 1/216 is the odds of getting three doubles in a row so I suppose the odds of not rolling three in a row is 215/216 or 99.54% chance.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
About 1.5% The odds of rolling a 7 on any particular throw is 1/6. (There are six ways you can roll a seven: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), out of 36 possible outcomes.) Therefore, the odds that you don't roll a 7 on a particular roll is 5/6. The odds that you don't roll a 7 in 23 rolls is: (5/6)^23, or approximately .015=1.5%
The probability is 1 - (5/6)3 = 1 - 125/216 = 91/216 = 0.42 approx.
The odds are 1:36
Rolling 2 twice in a row in the first two rolls is 1/6*1/6 = 1/36. But rolling 2 twice eventually is as close to certainty as you can get.