The probability is 11/36.
This is easiest to work out in the "negative":
Instead of working out all the "positive", or successful, outcomes and adding them together, the fact that the sum of all probabilities is 1 is used by working out all the "negative", or unsuccessful, outcomes, adding them together and subtracting this sum from 1:
For this case there are 3 positive (successful) outcomes: 6x, x6, 66 (where each pair represents the value showing on the dice (in order) with x meaning any digit 1-5) but only 1 negative (unsuccessful) outcome: xx.
Thus the calculation is:
Pr(at least one of the dice showing a six) = 1 - Pr(neither die shows a six).
The probability of a single die not showing a six is 5/6
→ the probability of two dice not showing a six is 5/6 × 5/6 = 25/36 as the two events are independent.
→ The probability of at least one six = 1 - probability of no six = 1 - 25/36 = 11/36.
It can be worked out in the positive, but requires much more work:
Pr(at least one 6) = Pr(6x: first die 6, second not 6) + Pr(x6: first not 6, second 6) + Pr (66: both 6)
= 1/6 × 5/6 + 5/6 × 1/6 + 1/6 × 1/6
= 5/36 + 5/36 + 1/36
= 11/36 (as before)
One out of six, or 16.6666...%.
There is a one out of four chance of having both dice even numbers.
The odds of rolling any specific number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling the same specific number using six dice in one roll is 1 in 6 to the 6th, or 1 in 46,656.
1 in 23328
Rolling one die, it is 1/6. Rolling two dice, it is 2/6, which can be simplified to 1/3 or 33.33%.
-3
One out of six, or 16.6666...%.
There is a one out of four chance of having both dice even numbers.
The odds of not rolling a 1 or 2 with two dice is 35 in 36. The odds of doing that 25 times in a row is (35/36)25 or about 0.4945Note: The odds of not rolling a 1 is zero, so the answer degraded to the odds of not rolling a 2.===================================Opinion #2:-- There are 36 possible outcomes when 2 dice are rolled.-- Only one of the outcomes is a 2.-- So the probability of NOT rolling a 2 with 2 dice is 35/36 .-- In 25 consecutive rolls, the probability of never rolling a 2 is (35/36)25 = 49.45% .-- The 'odds' are 1,011 to 989 against it.
The odds of rolling any specific number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling the same specific number using six dice in one roll is 1 in 6 to the 6th, or 1 in 46,656.
12/18 - 6/9 - 2/3
1 in 23328
Rolling one die, it is 1/6. Rolling two dice, it is 2/6, which can be simplified to 1/3 or 33.33%.
Impossible, you can't get 1-6 with only 5 dice.
With one roll of three dice, the probability is 7/8.
The odds of rolling any number in one roll of one die is 1 in 1. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll is 1 in 1 times 1 in 6, or 1 in 6.Now, look at the second pair of dice. The odds of rolling any number other than a number on the first pair is 5 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not the pair in the first roll is 5 in 6 times 1 in 6, or 5 in 36.Now, look at the third pair of dice. The odds of rolling any number other than a number on the first two pairs is 4 in 6. The odds of rolling the same number in one roll of one die is 1 in 6. Each die is unrelated, so the odds of rolling a pair using two dice in one roll, not one of the first two pairs is 4 in 6 times 1 in 6, or 4 in 36.To compute the total odds of rolling three pairs of numbers using 6 dice, simply multiply these odds together. That is 1 in 6 times 5 in 36 times 4 in 36, or 30 in 7776. Reducing that to lowest common fraction, you get 5 in 1296.(This calculation assumes that the three pairs are different. If two or three of the pairs are allowed to be the same, the computation is different.)
The probability of rolling at least one '1' with six dice is 66.5% [1-(5/6)^6]*100%