y>=-1/4
Restate the question: "What is the range of the function f(x) =x2+5x+6?".
If this is not your question, please clarify and ask the question again. :-)
Solve the quadratic x2+5x+6=0 <=> (x+2)(x+3) = 0 <=> x=-2 or x=-3. The minimum value is at x = (-2+-3)/2 = -5/2. The minimum value will be f(-5/2) = (-5/2)2+5(-5/2)+6 = 25/4-25/2+6 = (25-50+24)/4 = -1/4.
The range (or set of possible values) is f(x)>= -1/4 ... all numbers greater than or equal to -1/4.
5x6=30
x2≤64
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
x2 + 5x =6 x2+5x -6 = 0 (x+6)(x-1) = 0 x+ 6 = 0 x = -6 x-1 = 0 x = 1
30
5x6=30
x2≤64
what is the value of 5x6 =n
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.
5
The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
x2 + 5x =6 x2+5x -6 = 0 (x+6)(x-1) = 0 x+ 6 = 0 x = -6 x-1 = 0 x = 1
1
30
x2 = 16take the root square for both sides the result will be :X = +4 or -4