124x = 7 Divide both sides by 124: x = 7/124 = 0.056
At the x-intercept, y=0 so...2y - 4x = -122(0) - 4x = -12-4x = -124x = 12x = 12/4x = 3
5x-8 = x+125x-x = 8+124x = 20x=5
4x - 7y = 12-7y = -4x + 12y = (4/7)x - (12/7)======================4x - 7y = 124x = 7y + 12x = (7/4)x + 3
I assume you mean 3x - 8 = 12 - xif we move the x's to one side and the numbers to the other side:3x - 8 + x = 12 - x + x4x - 8 = 124x - 8 + 8= 12 +84x = 204x/4 = 20/4x = 5I hope that answers your question but if you would like further information please email me at charris321@wikianswers.com
124x = 7 Divide both sides by 124: x = 7/124 = 0.056
At the x-intercept, y=0 so...2y - 4x = -122(0) - 4x = -12-4x = -124x = 12x = 12/4x = 3
5x-8 = x+125x-x = 8+124x = 20x=5
4x - 7y = 12-7y = -4x + 12y = (4/7)x - (12/7)======================4x - 7y = 124x = 7y + 12x = (7/4)x + 3
124x.40=49.60 124-49.60=74.40 answer: 74.40
4x + 5(x - 2) +124x + 5x - 10 + 129x + 2
I have 2 M0F0-124X in 2 separate single ported boxes. What amp should I buy for these subs that would produce the loudest and best sound? Also, the m0f0 124x says it has a rms of 1500 watts, and i was told by a few people that, that number is quite an overshot, does anyone know the actual rms of these subs?
the specs are: ProcessorAMD Phenom II X6 1100T 3.3GHzProcessor Main Features64 bit Six-Core ProcessorCache Per Processor6 x 512KB L2 Cache 6MB L3 CacheMemory8GB DDR3 1333MHzHard Drive1.5TB SATA-IIOptical Drive 124X DL DVD+/-RW DriveGraphicsAMD Radeon HD 6970 (2 GB)
I assume you mean 3x - 8 = 12 - xif we move the x's to one side and the numbers to the other side:3x - 8 + x = 12 - x + x4x - 8 = 124x - 8 + 8= 12 +84x = 204x/4 = 20/4x = 5I hope that answers your question but if you would like further information please email me at charris321@wikianswers.com
12 foot in 3 peicies in which two are of same lenght say as x and x and the third one is twice of other i.e. 2x thenx+x+2x = 124x=12x=3so two are of 3 foot each and one is of 6 feet long3,3,6
The second integer is 64 (128/2), so the first is 62 and the third is 66.OrLet the 1st integer be x and the 3rd integer be y.Since even integers differ by 2, then we have:y = x + 4x + y = 128x + x + 4 = 1282x = 124x = 62So the integers are 62, 64, and 66, and their sum is 192